Question

a car moving at 20 m/s stops in 0.1 seconds after applying brakes . find the acceleration and distance travelled before stopping ​

Answer 1

Answer:

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Explanation:

Acceleration due to friction (retardation) (a) = - μg=−0.9×10=−9m/s

2

Final velocity, v=0m/s

Initial velocity, u=20m/s

Applying formula: v

2

=u

2

+2as

Where s is the distance traveled by car before it come to rest.

⇒0

2

=20

2

+2(−9)s

⇒18s=400

⇒s=22.2 m