Question

A car moving at 30 m/s slows uniformly to a speed pf 5 m/s in a time of 4 s calculate the acceleration of car the/distance it moves in third second

Answer 1

u = 30 ms
v = 5 ms
t = 4s

a = (v-u) / t = 30-5 / 4 = 25/4 = 125/100 = 1.25 ms^-2

and, distance(s) = ut + 1/2(a)(t)^2 = (30)(4) + 1/2(1.25)(4)(4)
= 120 + 1.25(8) = 120 + 10 = 130 m

Thus acceleration = 1.25 ms^-2 and distance = 130 m

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Answer 2

Answer:given

U=30m/s ,v=5m/s,t=4sec, a=?

Explanation:

a=v-u/t

a=5-30/4

a=-6.25m/s