A car moving at 30m/s slows down uniformly to a speed of 10m/s in a time of 5.0s. Determine a) the acceleration of the car, and b) the distance it moves in the third second
Answers
Answered by
0
Answer:
Car A is at rest with an acceleration of 2 m/s. Car B is at a constant velocity of 50 m/s. Distance between them is 200 m.
Answered by
0
GIVEN:
V=30km/hr
U=10km/hr
T=5s
- 30*5/18
- 8.33m/s
- 10*5/18
- 2.77m/s
a) A=V-U/T
=8.33-2.77/5
=1.112m/s
Similar questions