a car moving at 36 kilometre per hour it attains a velocity of 72 kilometer per hour find the distance travelled in this time period
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Answer:
Explanation:
v1 = 36 km/ hr
v2 = 72km/hr
let the distance be x
average distance = total distance / total time
total distance = x + x = 2x
total time = distance / velocity
T1 = x / 36 hr
T2 = x / 72 hr
total time = x/ 36 + x / 72 = 2x + x / 72 = 3x / 72 hr
now, putting in formulae , (average distance = total distance / total time)
average distance = 2x / 3x / 72 hr
= 2x×72/3x
= 2 × 36
average distance = 72 m
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