Question

A car moving at 40 km/hr is to be stopped by applying brakes in the next 4 m. If the car weighs 2000 kg, what average force must be applied to stop it?

Answer 1

Given :

Speed =u= 40km/hr x 5/18 = 11.11 m/s

Final speed=v= 0 m/s

mass of the car=m= 2000kg

a=?

From Third equations of motion.

v²-u²=2as

a= v²-u²/2s

a=o²-(11.11)²/2x4

a=-123.4321/8

=-15.42 m/s²

Now  F= mx a

= 2000x -15.42

= - 3.1 x 10 ⁴ N

∴ The force applied to stop is 3.1 x 10⁴ N in opposite direction

Answer 2

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