A car moving at 40 km per hour is to be stopped by applying brakes in the next 4.0 M if the car weight 2000 kg what average force must be applied on it
Answers
Answered by
64
u=40km/h
40×1000/3600=11.11m/s
v=o
t= 4m =4×60 =240s
....
force=m×(v-u/t)
force = 2000×(0-11.11/240)
force =-92 .58N
40×1000/3600=11.11m/s
v=o
t= 4m =4×60 =240s
....
force=m×(v-u/t)
force = 2000×(0-11.11/240)
force =-92 .58N
Answered by
26
Answer:
Explanation:
u=40km/h
40×1000/3600=11.11m/s
v=o
t= 4m =4×60 =240s
....
force=m×(v-u/t)
force = 2000×(0-11.11/240)
force =-92 .58N
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