a car moving at 40 km per hour is to be stopped by applying brakes in the next 4.0 M if the car weighs 2000 kg, what average force must be applied on it?
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Answered by
6
HLO FRIEND:--
m ( Mass) = 2000kg
u ( starting velocity) = 40km/h = 40*5/18= 144m/s
v ( Ending velocity ) = O
s ( distance) = 4 m
a ( Acceleration) =
_______________________
v^2 = u^2 + 2as
0 = 144^2 + 2 * a * 4
0 = 20736 + 8a
- 8a = 20736
- a = 20736/8 = 2592m/s^2
RETARDATION a = 2592m/s^2
Force (F ) = ma
= 2000* 2592 = 5184000N
I HOPE ITS HELP U:-)
m ( Mass) = 2000kg
u ( starting velocity) = 40km/h = 40*5/18= 144m/s
v ( Ending velocity ) = O
s ( distance) = 4 m
a ( Acceleration) =
_______________________
v^2 = u^2 + 2as
0 = 144^2 + 2 * a * 4
0 = 20736 + 8a
- 8a = 20736
- a = 20736/8 = 2592m/s^2
RETARDATION a = 2592m/s^2
Force (F ) = ma
= 2000* 2592 = 5184000N
I HOPE ITS HELP U:-)
Answered by
1
Answer:
3.08×10000
Explanation:
See the attachment below
Attachments:
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