Question

a car moving at 40 km per hour is to be stopped by applying brakes in the next 4.0 M if the car weighs 2000 kg, what average force must be applied on it?

Answer 1

HLO FRIEND:--

m ( Mass) = 2000kg

u ( starting velocity) = 40km/h = 40*5/18= 144m/s

v ( Ending velocity ) = O

s ( distance) = 4 m

a ( Acceleration) =
_______________________

v^2 = u^2 + 2as

0 = 144^2 + 2 * a * 4

0 = 20736 + 8a

- 8a = 20736

- a = 20736/8 = 2592m/s^2
RETARDATION a = 2592m/s^2

Force (F ) = ma
= 2000* 2592 = 5184000N

I HOPE ITS HELP U:-)

Answer 2

Answer:

3.08×10000

Explanation:

See the attachment below