Question

A car moving at 5.35 m/s picks up speed at a rate of 4.25 m/s/s for 34.6 m. What is the final velocity?

Answer 1

Given:-

• Initial velocity (u) = 5.35m/s

• Acceleration (a) = 4.25m/s²

• Distance (s) = 34.6m

To Find:-

• Final velocity of the car (v) .

Solution:-

By using 3rd equation of motion

→ v² = u² +2as

Substitute the value we get

→ v² = (5.35)² + 2×4.25 ×34.6

→ v² = 28.6225 + 8.50×34.6

→ v² = 28.6225 + 294.1

→ v² = 322.7225

→ v = √322.7225

→ v = 17.96 ≈ 18m/s

∴ The final velocity of the car is 18m/s.

Answer 2

Answer:

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