a car moving at 6 km per hour is to be stoppered by applying brakes in the next 5.0 m if the ka waiting 2500kg what Everest force must be applied on it
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Answer:
s=40m,v=0,u=40×
18
5
=
9
100
m/s
u
2
=2as
(
9
100
)
2
=2×a×40
9
100
×
9
100
=2×40×a
a=
81×8
1000
Force=ma
=2000×
81×8
1000
Force =3.086KN
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