Question

A car moving at 72km/h is stopped in 5 seconds.If it retards uniformly find the distance travelled by the car before it stops.Also find its retardation.​

Answer 1

Answer:

Distance traveled =50meter

Retardation =4m/s^2

Step-by-step explanation:

Given

Speed=72km/hr=20m/s

Time=5s

We use the formula S=ut+1/2at^2

S=20 x 5 -1/2 x 4 x 25

S=50meter

There is minus 1/2 because of the retardation

Retardatin= v-u/t

As we know the car has sotoped so the final velocity is 0m/s

Then

0-20/5=4m/s^2

4m/s^2 is the retardation

Answer 2

Answer:

4s/m..................