Question

A car moving at 90 km/h applies brakes and comes to stop in 4s. Find the acceleration of the car​

Answer 1

Answer:

here is the answer of

Explanation:

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Answer 2

Explanation:

Given that,

$Acceleration a=−0.5m/s2$

$Speed v=90km/h=25m/s$

Using equation of motion,

v=u+at

Where

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Finally train will be rest so, final velocity,v=0

0=25−0.5t

$</p><p></p><p>25=0.5t</p><p>$

$t = \frac{25}{0.5}$

$t=50 sec$

Again, using equation of motion,

$s=ut+ \frac{1}{2}a {t}^{2}$

Where, s = distance

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stop

$s=25×50− \frac{1}{2} ×0.5× {50}^{2}$

$s=625 m$

So, the train will go before it is brought to rest is 625 m.

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