a car moving at a constant speed of 36 km per hour moves with North words for 20 minutes then due to West with the same speed for 25 by 3 minutes what is the average velocity of the car during this run in kmph
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2
Answer:
I do
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Answered by
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Answer:
Explanation:
=> Here, a car moving at a constant speed of 36 kmph moves north wards for 20 minutes.
Speed = 36 km / h
Time, t1 = 20 mins = 20/60 hours = 1/3 hours (because 1 min = 1/60 hours)
Distance travelled towards north, S1 = Speed * time (t1)
= 36 km/h * 1/3 h
= 12 km
=> Car move towards west with the same speed for 8 * 1/3 minutes. Thus,
Speed = 36 km/h
Time, t2 = 8 * 1/3 = 25 / 3 minutes = 25 / 3 * 1/60 h = 25 / 180 h= 5/36 h
Distance travelled towards west, S2 = Speed (s) * time (t2)
= 36 * 5 / 36
= 5 km
Now, the average velocity of the car during this run:
V_avg = ΔS / Δt
= √ S1² + S2² / t1 + t2
=√(12)²+(5)²/(1/3+5/56)
= 13 * 36 / 17
= 27.5 km/h
Thus, the average velocity of the car during this run is 27.5 km/h.
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