Question

A car moving at a speed of 10m/second is stopped producing a retardation of 5m s-2 . How much distance will be covered by scooter before it stops

Answer 1

Explanation:

u=10m/s

v=0m/s

a= - 0.5m/s²

we know that

v² - u²=2as

0-100=2(-0.5)s

s=100m

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Answer 2

Answer:

Explanation:

HERE WE KNOW THAT

u=10m/s

and a=5m/s

we use v2-u2=2as

now put values

0^2-10^2=2.(-10).s

-100=-20.s

-100/-20=s

5m/s=s