A car moving at a steady 10 m/s on a level highway encounters a bump that has a circular cross-section with a radius of 30 m. The car maintains its speed over the bump. a) What is the centripetal acceleration of the car? (b) What is the normal force exerted by the seat of the car on a 60.0-kg passenger when the car is at the top of the bump?
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Answered by
3
Answer:
(a) 388 newton
(b) 17.15 m/s
Explanation:
r = 30 m
v = 10 m/s
m = 60 kg
(a) Let N be the normal reaction.
At the bump
N = mg - mv^2 / r
N = 60 x 9.8 - 60 x 10 x 10 / 30 = 588 - 200 = 388 newton
(b) Then the contact loose, N = 0
So, mg = mv^2 / r
v^2 = r x g = 30 x 9.8 = 294
v = 17.15 m/s
(a) 388 newton
(b) 17.15 m/s
Explanation:
r = 30 m
v = 10 m/s
m = 60 kg
(a) Let N be the normal reaction.
At the bump
N = mg - mv^2 / r
N = 60 x 9.8 - 60 x 10 x 10 / 30 = 588 - 200 = 388 newton
(b) Then the contact loose, N = 0
So, mg = mv^2 / r
v^2 = r x g = 30 x 9.8 = 294
v = 17.15 m/s
Answered by
0
As we know that,
Given:
A car moving at a steady 10 m/s on a level highway.
with a radius of 30 m.
Find out:
a) What is the centripetal acceleration of the car?
(b) What is the normal force exerted by the seat of the car on a 60.0-kg passenger when the car is at the top of the bump?
Let us:
/
so,
a) N be the normal reaction.
At the bump
- ^
x - x x
The centripetal acceleration of the car
then,
b) the contact loose,
^
^r x x
The normal force
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