A car moving at a uniform speed covers a distance of 200 min 4s.calculate 1) the speed of the car 2) the time it will take to cover 300km 3) the distance it will cover in 5s
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Solution :-
Part I
- Distance traveled( d) = 200 m
- time taken ( t) = 4 s
we know that ,
⟹ s = d / t
⟹ s = 200 /4
⟹ s = 50 m /s
Part II
- Speed (s) = 50 m/s
- Distance traveled ( d ')= 300 m
we know that ,
⟹ s = d ' /t
On rearranging ,
⟹ t ' = d ' / s
⟹ t ' = 300 / 50
⟹ t ' = 6 s
Part III
- Speed (s)= 50 m/s
- Time taken (t ")= 5 s
we know that ,
⟹ s = d " /t "
On rearranging ,
⟹ d " = s x t "
⟹ d " = 50 x 5
⟹ d " = 250 m
Answer
- The speed of the car is 50 m /s
- The time it will take to cover 300km is 6s
- The distance it will cover in 5sm is 250m
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