a car moving at the speed of 12m/s
it applies break and stops in 18 metres find its acceleration
Answers
Answered by
1
Speed = 12 m/s
u = 18 m
v = 0
a = v-u/t
a= v-u / D/s
a= 0-18 / 18/12
a= -18/ 3/2
a= -18×2/3
a= -12 m/s²
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Answered by
0
Answer:
4
Step-by-step explanation:
u = 12m/s ; s = 18m, v = 0
a = ? (a is negative as its retarding)
v² - u² = 2as
=> 0 - 144 = 2(-a)18
=> 144 = 36a
=> a = 4 m/s²
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