A CAR MOVING IN A SPEED OF 54 Km/h ACCELERATES TO 126 Km/h IN 10 SECONDS. FIND THE ACCELERATION OF THE CAR AND DISPLACEMENT
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v = 126 km/h = 35 m/s
u = 54 km/h = 15 m/s
t = 10 sec
By 1st law of motion,
v= u +at
⇒35= 15 + a×10
⇒20 = 10a
⇒a = 2 m/s²
By 3rd equation of motion,
v²- u² = 2as
⇒(35)²-(15)² = 2×2×s
⇒4s = 1000
⇒s = 250 m
u = 54 km/h = 15 m/s
t = 10 sec
By 1st law of motion,
v= u +at
⇒35= 15 + a×10
⇒20 = 10a
⇒a = 2 m/s²
By 3rd equation of motion,
v²- u² = 2as
⇒(35)²-(15)² = 2×2×s
⇒4s = 1000
⇒s = 250 m
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