Question

a car moving on a straight highway with in the distance of 200 metre .what is the retardation of car and how long does it take for car to stop?

Answer 1

According to Newtons 3rd law

Every action force has an equal and opposite reaction which acts simultaneously

Hence it depends upon the amount of gas released by the car by which the car is moved

For another example consider a rocket

It takes same amount of pressure by gases to raise the rocket upwards to escape earths escape velocity that is 11.2 km/s

Answer 2

==============ⓢⓦⓘⓖⓨ

$\huge\mathfrak\red{hello...frd\:swigy\:here}$

==============ⓢⓦⓘⓖⓨ

Initial velocity of the car, u = 126 km/h = 35 m/s

Final velocity of the car, v = 0

Distance covered by the car before coming to rest, s = 200 m

Retardation produced in the car = a

From third equation of motion, a can be calculated as:

V^2 - U^2 = 2aS

(0)^2 - (35)^2 = 2 . a . 200

a = ( 35×35)/(2× 200)

a= 3.06 m/ s^2

From first equation of motion, time (t) taken by the car to stop can be obtained as:

V = U + at

t = (V- U )/a = (-35)/(-3.06) = 11.44 sec

I hope, this will help you

=======================

$<marquee behaviour-move bigcolour-pink><h1>☺ThankYou✌</h1></marquee>$

·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·

___________♦♦⭐♦ ♦___________