Question

A car moving on a straight road accelerates from a speed of 4.1m/s to a speed of 6.9m/s in 5.0sec .What was it's average acceleration

Answer 1

Initial velocity, u=4.1ms−1u=4.1ms−1

Final velocity, v=6.9ms−1v=6.9ms−1

Time in which change occurs, t=5sect=5sec.

Using the relation v=u+atv=u+at, (where aa is the acceleration), we get for

a=6.9ms−1−4.1ms−15s=2.8ms−15s=2.85ms−2=0.56ms−2a=6.9ms−1−4.1ms−15s=2.8ms−15s=2.85ms−2=0.56ms−2

So, the average acceleration, a=0.56ms−2

Answer 2

average acceleration= final speed-initial speed/time taken=6.9-4.1/5 = 2.8/5=0.56m/s^2 . Hope it helps you...Mark me as Brainliest.