Question

A car moving on a straight road at 5 m/s. It is accelerated at 3 m/s^2. What will be its velocity after 4 seconds ?​

Answer 1

Answer:

Its velocity after 4 seconds will be 7 m/s.

Explanation:

Given:

Initial velocity of the car (u) = 5 m/s

Acceleration of the car (a) = 3 m/s^{2}2

Time (t) = 4 seconds

To find:

Velocity after 4 seconds.

Solution:

We will find the velocity using the first equation of motion.

v = u + at

where v is final velocity

u is initial velocity

a is acceleration

and t is time.

Now substitute the given values, we get

v = u + at

=> v = 5 + 3 × 4

=> v = 5 + 12

=> v = 17 m/s.

Answer 2

Given:-

• A car moving on a straight road at 5 m/s.
• It is accelerated at 3 m/s^2.
• Time Taken is 4 seconds.

Find:-

→ What will be the velocity after 4 seconds.

Solution for the problem :-

So, we have to find the velocity of the car.

⠀⠀⠀⠀⠀★ Working Rule

There are three equations for the motion of those bodies which travel with a uniform acceleration. These equations give relationship between initial velocity, final velocity, time taken, acceleration and distance travelled by the bodies.

Here we are gonna use first equation of motion

The first equation of motion is :-

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀v = u + at

It gives the velocity acquired by a body in time t.

Here,

" u " is the initial velocity of the car .

" a " is the acceleration

" t " is time taken

" v " is the final velocity of the car.

Therefore , now putting up the values.

v = u + at

→ u = 5 m/s

→ a = 3 m/s²

→ t = 4 sec$.$

⇒ v = 5 + 3 × 4

⇒ v = 5 + 12

⇒ v = 17 m/s.

Thus, the initial velocity of the car is 17 metre per second.

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