Question

A car moving on a straight road at 5 m/s. It is accelerated at 3 m/s^2. What will be its velocity after 4 seconds ?​

Answer 1

Given :

• Initial velocity, u = 5 m/s
• Acceleration, a = 3 m/s²
• Time taken, t = 4 seconds

To find :

• Final velocity, v

According to the question,

➞ v = u + at [First equation of motion]

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

➞ Substituting the values,

➞ v = 5 + 3 × 4

➞ v = 5 + 12

➞ v = 17

• So, the final velocity is 17 m/s.

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More formulas :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as

Answer 2

Answer:

Given :-

• A car is moving on a straight road at 5 m/s. Acceleration is 3 m/s² and its time is after 4 seconds.

To Find :-

• What is its velocity.

Formula Used :-

★ v = u + at ★

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

Solution :-

Given :

• Initial velocity = 5 m/s
• Acceleration = 3 m/s²
• Time = 4 seconds

According to the question by using the formula we get,

⇒ v = u + at

⇒ v = 5 + 3(4)

⇒ v = 5 + 12

➠ v = 17 m/s

∴ The velocity is 17 m/s .

✠ Extra Information ✠

➤ Newton's First Law :-

• Newton's 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion untill and unless a net external force acts to it.

➤ Newton's Second Law :-

• Newton's 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force in the same direction.

➤ Newton's Third Law :-

• Newton's 3rd law states that for every action that is an equal and opposite reaction.

✪︎ Important Formula ✪︎

✧ First equation of motion :-

⋆ v = u + at ⋆

✧ Second equation of motion :-

⋆ s = ut + ½ at² ⋆

✧ Third equation of motion :-

⋆ v² = u² + 2as ⋆