Question

a car moving on a straight road covers the one fourth the total distance with 36km/h and the rest with 54km/h the average speed of car is​

Answer 1

Answer:

48 m/s

Explanation:

we know, s = d/t

if the car covered d/4 with a speed of 36, then t1 = d1/4/36

t1 = d/144 (since t = d/s and d1 = 1/4 of d)

and similarly, t2 = 3d/4/54 = d/72

we know avergae speed = total distance / total time

total distance = d, total time = t1 + t2

total time = d/144 + d/72 = 3d/144 = d / 48

therefore, average speed = d/d/48

or 48m/s