A car moving over a straight path, covers
a distance d with constant speed of
40 km/hr and then the same distance with
speed 60 km/hr. The average speed of car
is .........
Answers
ANSWER :
Given :
▪ A car covers first half of total distance with speed 40kmph and second half of total distance with speed 60kmph.
To Find :
▪ Average speed of the car.
Concept :
✏ If body covers first half of total distance with speed v1 and second half of total distance with speed v2, then average speed of the body is given by
☞ (v)av = 2v1v2/v1+v2
✏ Average speed is defined as the ratio of total distance travelled to the total time taken.
✏ It is a scalar quantity.
Calculation :
→ (v)av = 2v1v2/v1+v2
→ (v)av = 2(40)(60)/(40+60)
→ (v)av = 4800/100
→ (v)av = 48kmph
Given:
A car moving over a straight path, covers a distance d with constant speed of 40 km/hr and then the same distance with speed 60 km/hr.
To Find:
Average speed of car for given time interval
Solution:
It is given that,
Firstly, car travelled distance 'd' with velocity 40 km/hr and travelled distance d again with velocity 60 km/hr
So,
Total distance covered by car,
D= d+d= 2d
Let t₁ be the time taken by car to cover distance d with velocity 40 km/hr and t₂ be the taken by car to cover distance d with velocity 60 km/hr
We know that,
So,
Now,
Hence, the average speed of car for given time interval is 48 km/hr.