Question

A car moving towards north at a speed of 10 m/s
turns right within 10 s maintaining the same speed.
Average acceleration of the car during this time
interval is
(1) 1/2^1/2 m/s^2 S-W
(2) 1/2^1/2 m/s^2 N-E
(3) 2^1/2 m/s ^2 S-E
(4) 2^1/2 m/s^2N-E​

Answer 1

Answer:

(3)

Explanation:

Vf = 10 i

Vi = 10 j

∆V = Vf - Vi = 10 i - 10 j

a = ∆V / ∆t = i - j

|a| = √2 m/s^2 towards S-E