Question

A car moving towards North at a speed of 5 m/s turns right within 10 s and maintaining the same speed. The change in magnitude of velocity of car is?​

Answer 1

Answer:

So, initial velocity due north (u)= 5m/s

Final velocity east (v) = 5 m/s

Time interval (t) = 10 s

Following vectors:- √5²+5²=√50= 5√2 m/s=change in velocity

So, acceleration (a)=v-u/t

= 5√2 / 10

= √2 / 2 m/s