Question

a car moving towards north at aspeed of 10m/s turns right within 10s maintaining the same speed.average acceleration of the car during this time interval is​

Answer 1

Answer:

(3) √2 m/s^2 S-E

Explanation:

∆V = Vf - Vi

|∆V| = √(|Vf|^2 + |Vi|^2) = 10√2 m/s

direction of ∆V : S-E

Average acceleration = |∆V| / t = 10√2 / 10

= √2 m/s^2