a car moving wih a velocity of 40m/s . due to friction its velocity decreases to the rate of 0.05 m/s^2.how much time will it take for the body to stop
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V=u+at
U=40m/s
A=-.05
V=0
Therefore t=-40/-.05= 800 seconds
backbencher007:
thank you so much
Oh sorry
no worries
I have taken t=.5sec but it is .05
yay but no problem you explained it really well
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