Question

A car moving with 54km/h applies a break which produces an acceleration on 3m/s in opposite direction of motion after how time the car will stop after applying brake

Answer 1

Initial speed of the car (u) = 54 km/h = 15 m/s

Final speed of the car (v) = 0 m/s

Acceleration produced by brakes in opposite direction = - 3 m/s^2

Let the time taken to stop the car be t

Using first equation of motion:

v = u + at

0 = 15 - 3 × t

$t = \frac{15}{3}$

t = 5 seconds

Hence, the time taken by the car to come to rest is 5 seconds.