Question

A car moving with a constant velocity of 36km/h,steps for 10m on the breaking,find the acceleration and how much time it will take to stop?​

Answer 1

$v { }^{2} - u {}^{2} = 2as$

u=0m/s

v=36km/hr×5÷18=10m/s

distance(s)=10m

$10 {}^{2} - 0 {}^{2} = 2 \times a \times 10$

100÷20=a

$a = 5ms {}^{2}$

a=v-u÷t

t=v-u÷a

10-0÷5=t

$t = 2sec$

Answer 2

here is your answer ....