Question

A car moving with a speed of 108 km/h comes to rest after 4 s on applying
brake.
If the mass of the car including the passengers is 1000 kg, what will be
the force applied when brake is applied?​

Answer 1

Answer:

5N Newton is the correct answer

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Answer 2

Answer:

Intial velocity of the car u =

$108 \: km/h \: = \: 108 \times \frac{1000}{60 \times 60} \\ = 108 \times \frac{5}{18} = 30m/s$

Final velocity v = 0

Mass M = 1000 kg

Time t = 4 s

According to Newton's second law of motion

F = ma

$f \: = m \times \frac{(v - u)}{t} = \frac{1000(0 - 3)}{4} \\ \\ = - 7500N$

The Negative (-) sign indicates that the Applied force is opposite to the Direction of motion .