)A car moving with a speed of 126 km/h is brought to a stop within a
distance of 200 m. Calculate the retardation of the car and the time
required to stop it.
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A car moving with a speed of 126 km/h is brought to a stop within a distance of 200 m. Calculate the retardation of the car and the time required to stop it.
a = -30.625 ; t = 1.1428 sec
Given:-
u = 126km/h ; v = 0 ; s = 200m
Formulas:-
- v² - u² = 2as
- v = u + at
- s = ut + 1/2 at²
0² - 35² = 2(a)(200)
1225 = 400a
a = 1225/400
a = -30.625
v = u + at
0 = 35 + (-30.625)t
-35 = -30.625t
t = -35/-30.625
t = 1.1428 sec
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