Question

A car moving with a speed of 15 m/s can be stopped by applying brake
after travelling a distance of 3 m. The retardation of car is
​

Answer 1

GIVEN~ u (initial velocity) = 15m/s

v (final velocity) = 0

s (distance) = 3m

TO FIND~ Retardation = ?

SOLUTION~

As we know ,

v^2 = u^2 + 2as

0^2 = 15^2 + 2 × a × 3

0 = 225 + 6a

-225 = 6a

-225/6 = a

-37.5 = a

therefore the retardation of the car is -37.5m/s^2