A car moving with a speed of 15 m/s can be stopped by applying
brakes, after travelling a distance of 3m. The retardation of the car is
1) 37.5m/s² 2) 47.5m/s² 3) 57.5m/s² 4) 67.5m/s
Answers
Answered by
1
Explanation:
SOLUTION~
As we know ,
v^2 = u^2 + 2as
0^2 = 15^2 + 2 × a × 3
0 = 225 + 6a
-225 = 6a
-225/6 = a
-37.5 = a
therefore the retardation of the car is -37.5m/s^2
Answered by
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QUESTION:
A car moving with a speed of 15 m/s can be stopped by applying brakes, after travelling a distance of 3m. The retardation of the car is.
ANSWER:
37.5m/s²
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