Question

a car moving with a speed of 20 metre per second can be stopped by applying brakes after travelling a distance of 2 metres the retardation of the car is​

Answer 1

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Answer 2

Answer:

100m/$s^{2}$

Explanation:

$v^{2}$ - $u^{2}$  =  2as

0 - $20^{2}$  =  2 * a * 2

- 400   =  4 * a

     a    =   - 400 / 4

     a    =   - 100 m/$s^{2}$

retardation  =  -a

                   =    100 m/$s^{2}$