Question

A car moving with a speed of 20m/s is brought to rest in 10s by applying brakes.
find :

a) the magnitude for retardation due to brakes

b) distance travelled by the car after applying brakes.​

Answer 1

Answer:

(a) 2m/$s^{2}$

(b)100m

Explanation:

Here, u=20, t=10s, v=0

(a) V=u+at⇒0=20+a(10)⇒-20=10a⇒a=-2m/$s^{2}$

(b) S=ut+(1/2)a$t^{2}$=20 X 10+(1/2) X -2 X $10^{2}$=200-100=100m