. A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2 m. If the same car is
moving with a speed of 80 km/h, what is the minimum stopping distance
Answers
Answered by
21
Given
Speed of carA = 40km/h
- for m/s = 40 × 5/18 = 200/18
- U = 200/18
- V=0 because of applying break
- s= 2m
_______________
speed of car A = 80km/h
- for m/s = 80 × 5/18 =400/18m/s
- v=0 applying break
To find
Distance taking after applying break.
Solution
From equation of motion
V²=u²+2as
=>0=u²+2as
=>-2as=u2
=>a=u²/-2s
=>a=-30.864
Here - sign indicate that the car retardat
Now coming to v=400/18m/s
V²=u²+2as
=>-2×-30.864s=(400/18)²
=>s=8
Answered by
36
Answer:
Given:
- A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2 m. If the same car is moving with a speed of 80 km/h.
Find:
- What is the minimum stopping distance.
Know terms:
- Initial velocity = (u)
- Final velocity = (v)
Note:
- 40 = 40 * 5/18
- 200/18
Using formula:
- v² = u² + 2as
Calculations:
⇒ a = -u²/2s
⇒ a = -30.864 m/s²
⇒ u = 80
⇒ 400/18 m/s
⇒ a = -30.864 m/s²
Using formula again, we get:
⇒s = -u²/2a
⇒ 8 m
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