A car moving with a speed of 40km/hr can be stopped by applying brakes atleast after 2m. if the same moving with the speed of 80km/hr what is the minimum stopping distance
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Answer:
8km
Step-by-step explanation:
v2-u2=2as
substituting v=0, u=40 km/hr, s=2 km
0-40 square=2×a×2
a=400 km/hr square
for u=80 km/hr
0-80 square=2×(-400)×s
s=6400/800= 8 km
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