Question

A car moving with a speed of 40km/hr can be stopped by applying brakes after at least 2m. If the same car is moving with a speed of 80km/hr,what is the minimum stopping distance

Answer 1

Hy...
Friend...

Initial velocity
u = 40 km/h
= 40 × (5/18)
= 200/18 m/s

Final velocity
v = 0

Distance travelled before coming to
rest.
s = 2 m

Using
v2 = u2 + 2as

=> a = -u2/(2s)

=> a = -30.864 m/s2

Again

u = 80 km/h
= 400/18 m/s

v = 0

a = -30.864m/s2

Now
v2 = u2 + 2as

=> s = -u2/(2a) = 8 m


I hope its helps you
Thankyou you asking question
Be brainly

Answer 2

if the car is moving with speed 40km/h,
stopped by applying brakes after at least 2m.
:. u= 40km/h
v=0
s=2m
so ,u" will become,
40*5/18
=200/18

v2=u2+2as
a= -30.864 m/s2

:. u= 80
=400/18
v=0

a=-30.864

v2=u2+2as
s=- u2/(2a)
= (400/18)2(2*-30.864)
= 8m


I hope you will understand.
Your lovely friend SINGHUM