Question

A car moving with a speed of 40km/hr can be stopped by applying brakes after at least 40m. If the same car is moving with a speed of 80km/hr,what is the minimum stopping distance

Answer 1

${v}^{2} - {u}^{2} = 2as$
${0}^{2} - {40}^{2} = 2a \times 40$
$a = 2$
NOW,
${v}^{2} - {u1}^{2} = 2 \times 2 \times s$
$\frac{6400}{4} = s = = = = = = = = = = s = 1600meters = 1.6km$
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