Question

a car moving with a speed of 40kmph can be stopped by applying brakes after atleast 2m.if the same car is moving with a speed of 80kmph,what is the minimum stopping distance?​

Answer 1

Answer:

=2.66km

Explanation:

Speed is u=

18

40×5

m/s=

9

100

m/s

We need to stop it in 120sec so acceleration a=

t

u

=

9×120

100

Minimum stopping distance will be s=

2a

v

2

=

2×100/1080

(80×5/18)

2

=2666.6m=2.66km

Answer 2

Explanation:

Speed is u=

18

40×5

m/s=

9

100

m/s

We need to stop it in 120sec so acceleration a=

t

u

=

9×120

100

Minimum stopping distance will be s=

2a

v

2

=

2×100/1080

(80×5/18)

2

=2666.6m=2.66km