Question

a car moving with a speed of 40m/s can be stopped by applying brakes in 2 m if the same acceleration exists after how much distance in which a car with velocity 80m/s can be stopped ​

Answer 1

Answer:

yes for this acceleration should be 400 m/ s^2

by solving for speed of 80 meter/s it will stop in 8 meter

Explanation:

Answer 2

⊕ANSWER⊕

Initial velocity, u = 40 km/h = 40 × (5/18) = 200/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 2 m

Using, v2 = u2 + 2as

=> a = -u2/(2s)

=> a = -30.864 m/s2

Again,

u = 80 km/h = 400/18 m/s

v = 0

a = -30.864m/s2

Now, v2 = u2 + 2as

=> s = -u2/(2a) = 8 m