A car moving with a speed of 50 km/h can be stopped by brakes
after at least 6m. what will be the minimum stopping distance, if the
same car is moving at a speed of 100 km/h?
Answers
Answered by
2
Given, u=50km/hr=50×
18
5
=
18
250
m/s
v=0
s=6m(at least)
By third equation by motion,
v
2
=u
2
+2as
0=(
18
250
×
18
250
)+2(−a)(s)
0=192.90−12a
a=
12
192.90
=16.07
Now applying third equation of motion,
v
2
=u
2
+2as
⟹0=(100×
18
5
)
2
+2(−16.07)(s)
⟹0=771.60−32.14s
⟹s=
32.14
771.60
=24.00
Answered by
2
Answer:
Given, u=50km/hr=50×
18
5
=
18
250
m/s
v=0
s=6m(at least)
By third equation by motion,
v
2
=u
2
+2as
0=(
18
250
×
18
250
)+2(−a)(s)
0=192.90−12a
a=
12
192.90
=16.07
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