A car moving with a speed of 50 km h can be stopped by brakes after at least 6 m if the same car is moving at a speed of 100 km h in the minimum stopping distance is
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BY APPLYING:
V^2 = U^2 + 2AS CONVERTING KM/H INTO M/S
WE GET: (50*1000)/(60*60)=13.88
0 = (13.88)^2 + 2A6
-(190.44) = 12A
A = (190.44/12)-
A = -15.87
again applying the same formula
0 = 27.8^2 + 2(-15.87)s convert 100 km/h into m/s
-772.84 = -31.74s
S = 772.84/31.74
S = 24.34
the minimum stopping distance is 24.34m.
V^2 = U^2 + 2AS CONVERTING KM/H INTO M/S
WE GET: (50*1000)/(60*60)=13.88
0 = (13.88)^2 + 2A6
-(190.44) = 12A
A = (190.44/12)-
A = -15.87
again applying the same formula
0 = 27.8^2 + 2(-15.87)s convert 100 km/h into m/s
-772.84 = -31.74s
S = 772.84/31.74
S = 24.34
the minimum stopping distance is 24.34m.
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