Question

a car moving with a speed of 50km/hr can be stopped by brakes after at least 6m. if the same car is moving at a speed of 100km/hr the minimum stopping distance is​

Answer 1

Explanation:

Given, u=50km/hr=50×

18

5

=

18

250

m/s

v=0

s=6m(at least)

By third equation by motion,

v

2

=u

2

+2as

0=(

18

250

×

18

250

)+2(−a)(s)

0=192.90−12a

a=

12

192.90

=16.07

Now applying third equation of motion,

v

2

=u

2

+2as

⟹0=(100×

18

5

)

2

+2(−16.07)(s)

⟹0=771.60−32.14s

⟹s=

32.14

771.60

=24.00

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Answer 2

Answer:

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