Question

a car moving with a speed of 54km hr is brought to rest by breaking in 75m.if the same road is in shape of horizontal surface of radius 6m , what can be it's maximum speed in (m/s) so that it can negotiate the curve?
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Answer 1

Answer:

Velocity of A ⇒54km/hr⇒15m/s.

Since the motion of B is seen in perpendicular direction by A.

∴ Its component of velocity will be 15 m/s in the direction of motion of A in same direction. Now Its velocity is 5 m/s in perpendicular direction .

$∴ Magnitude of velocity ⇒</p><p></p><p> \sqrt{5 {}^{5} + 15 {}^{2} ⇒ }$

$\sqrt{250} ⇒5 \sqrt{10}m/s at \: some \: angle \: away \: from \: the \: car.</p><p></p><p></p><p></p><p>$