Question

a car moving with a speed of 72 km/hr is brought to rest by applying breaks find the acceleration and distance traveled ​

Answer 1

Answer-

retardation = 2 m/s^2

distance covered = 100 m

Explanation:

given u=72 km/hr = 72×5/18 m/s = 20 m/s

v=0

t= 10 s

v=u+at

a =v-u/t

a = -2 m/s^2

retardation= 2 m/s^2

v^2 - u^2 = 2aS

S = v^2 - u^2 /2a

S = 100 m