A CAR MOVING WITH A SPEED OF 72KM STOPS IN 5S ON APPLICATION OF BRAKES ASSUMING THE RETARDATION TO BE UNIFORM FIND THE RETARDATION OF THE FORCE THE MASS OF THE CAR IS 100KG
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3
v= u+at
0= 20+ a ×5
a=-4m/s²
The car retards with the rate of -4m/s²
Force= ma
=100*-4=-400N
0= 20+ a ×5
a=-4m/s²
The car retards with the rate of -4m/s²
Force= ma
=100*-4=-400N
Answered by
0
72 kmph = 72 × 5/18 = 20 m/s
a = (v - u) / t
= (0 - 20) m/s / (5 s)
= -4 m/s²
Retardation of car is 4 m/s²
a = (v - u) / t
= (0 - 20) m/s / (5 s)
= -4 m/s²
Retardation of car is 4 m/s²
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