A car moving with a uniform velocity of 100m/s is decelerated at 2.5m/s square to stop. Calculate the time taken for the car to stop
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Answer:t=40s
Explanation:u=100m/s
v=0
Deceleration=2.5m/s^2
a=-2.5m/s^2
By equation of motion,
v=u+at
0=100-2.5t
-100=-2.5t
t=40s
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40 SECOND BECAUSE 100÷2.5 is 40 and car speed decreases by 2.5m/s
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