Question

a car moving with a velocity 24m/s is slowed down uniformly to half the initial velocity over a distance of 105m.What is the retardation?How much distance it would cover before coming to rest? ​

Answer 1

Step-by-step explanation:

Initial speed of the car is u.

Final speed of the car v=0

Let the retardation of the car be a.

Using v

2

−u

2

=2aS

Or 0−u

2

=2aS

⟹ S∝u

2

(for same a)

Given : S=40m u

′

=2u

∴

S

S

′

=

u

2

(u

′

)

2

=2

2

Or

40

S

′

=4

⟹ S

′

=160m