Question

. A CAR MOVING WITH A VELOCITY : 48 kmh is brought to rest in 11
seconds to avoid a collision with the wall. What is the acceleration of the car
How much distance will be covered before coming to rest?​

Answer 1

Answer:

the answer is -4.3636

Explanation:

We know that acceleration is= v-u/t and 0-48=-48

-48/10=-4.3636

Answer 2

Answer:

1.21m/s

Explanation:

Speed = 48km/h = 48 x 5/18 = 40/3 = 13.3 m/s

Time = 11 sec

Acceleration = v-u/t

where v=0

a = 0-13.3/11

= -13.3/11

= -1.21m/s